Question

A = (2, 5), B = (4, -11) and the locus of C is
9x + 7y + 4 =0 then the locus of the centroid
of AABC is
1) 27x+21)-8=0
3) 24x+22y-6=0
2) 3x+4y-2=0
4) 5x+3y-7=0​

Answer 1

Answer:

6-the extremities

triangle

of the

of the base of an isosceles

are the points (2a,0) and 10, a) and

of the sides is x=2a

the equation of one of

then

of the triangle

square

(A) 5/ a al

(3) 5/pa

units is :

(c) 250

4) sa

4