Question

પાસા ને અેકવાર ફેકવામા આવે તો
(a) 2 અને 6 વચ્ચે ની સંખ્યા ​

Answer 1

Question :-

If the aspect is thrown once  

(a) Number between 2 and 6

Solution :-

Possible outcomes when a die is thrown once = {1,2,3,4,5,6}  

Number of possible outcomes = 6  

(ii) Let F be the event of getting a number lying between 2 and 6  

Numbers lying between 2 and 6 on the die are = {3,4,5}  

Number of favourable outcomes = 3  

$\therefore$ $P(F)$ = $\frac{favourable\ outcomes}{total\ outcomes} = \frac{3}{6}$

$= \frac{1}{2}$

Therefore, the probability of getting a number lying between 2 and 6 is $\frac{1}{2}$

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