Math, asked by RishitaSurve, 1 year ago

(a^2-b^2) (a^2+b^2) -(a^2-b^2)^2
solve this
ans will be= -2b^4 +2a^2b^2

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Answers

Answered by akpranav
0

(a² - b²)(a²+b²) - (a²-b²)²

(a+b)(a-b)=a²-b²

=(a²)²-(b²)² - (a²-b²)²

=a∧4-b∧4 - (a∧4 + b∧4 - 2a²b²)

=a∧4 + b∧4 - a∧4 - b∧4 + 2a²b²

= -b∧4+2a²b²



RishitaSurve: are you pranav kashyap??
akpranav: no
RishitaSurve: whoops!!
Answered by gaurav2013c
0
( a^2 - b^2) (a^2 + b^2) - (a^2 - b^2)^2

= ( a^2 - b^2) [ a^2 + b^2 - ( a^2 - b^2)]

= ( a^2 - b^2) ( a^2 + b^2 - a^2 + b^2)

= ( a^2 - b^2) ( 2b^2)

= 2a^2 b^2 - 2b^4

= - 2b^4 + 2a^2 b^2
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