(a^2-b^2) (a^2+b^2) -(a^2-b^2)^2
solve this
ans will be= -2b^4 +2a^2b^2
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(a² - b²)(a²+b²) - (a²-b²)²
(a+b)(a-b)=a²-b²
=(a²)²-(b²)² - (a²-b²)²
=a∧4-b∧4 - (a∧4 + b∧4 - 2a²b²)
=a∧4 + b∧4 - a∧4 - b∧4 + 2a²b²
= -b∧4+2a²b²
RishitaSurve:
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( a^2 - b^2) (a^2 + b^2) - (a^2 - b^2)^2
= ( a^2 - b^2) [ a^2 + b^2 - ( a^2 - b^2)]
= ( a^2 - b^2) ( a^2 + b^2 - a^2 + b^2)
= ( a^2 - b^2) ( 2b^2)
= 2a^2 b^2 - 2b^4
= - 2b^4 + 2a^2 b^2
= ( a^2 - b^2) [ a^2 + b^2 - ( a^2 - b^2)]
= ( a^2 - b^2) ( a^2 + b^2 - a^2 + b^2)
= ( a^2 - b^2) ( 2b^2)
= 2a^2 b^2 - 2b^4
= - 2b^4 + 2a^2 b^2
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