A 24 volt battery is connected to an arrangement of resistances as shown in the figure
calculate :
a)the effective resistance or the resistors.
b)the total current flowing through it.
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total resistance =[( r1×r2)÷(r1+r2)]+ [(r3×r4)÷(r3+r4)]
=(25×10)÷(25+10) + (2×5)÷(2+5)
=250÷35 + 25 ÷7
=10.7142857143 ohm equivalent resistance
current = v ÷ r
= 24 ÷ 10.7142857143
=2.24 ampere
=(25×10)÷(25+10) + (2×5)÷(2+5)
=250÷35 + 25 ÷7
=10.7142857143 ohm equivalent resistance
current = v ÷ r
= 24 ÷ 10.7142857143
=2.24 ampere
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