A 280 ml mix real juice pack contain mixture of mango juice and orange juice in the ratio of 9:5 . if x ml juice taken out from pack & 20 ml of orange juice mixed in pack so the new ratio of mango juice & orange juice become 7:5 , then find what quantity of mango juice taken out from pack initially ?
Answers
Given:
A 280 ml mix real juice pack contain mixture of mango juice and orange juice in the ratio of 9:5 . if x ml juice taken out from pack & 20 ml of orange juice mixed in pack so the new ratio of mango juice & orange juice become 7:5.
To Find:
What quantity of mango juice taken out from pack initially.
Solution:
Given total quantity of juice = 280ml
The ratio of mango to orange juice parts is 9 : 5.
Thus, mango juice volume
= [9/(9+5)]×Total volume
= [9/14 × 280] ml
= 180 ml
Orange juice volume
= [5/14 × 280] ml
= 100 ml
Next, y ml of mango juice is taken out.
So, mango juice remaining = (180-y) ml
And, 20 ml orange juice is added.
So, orange juice now
= (100+20)ml
= 120ml
So, mango to orange juice ratio now is
= (180-y)/120
Given, this ratio = 7:5.
So, (180-y)/120 = 7/5
⇒840 = 900 - 5y
⇒ 5y = 60
⇒ y = 60/5
= 12 ml
So, 12ml of mango juice was removed earlier.
Answer:
y = 12ml.
- A 280 ml mix real juice pack contain mixture of mango juice and orange juice in the ratio of 9:5 . if x ml juice taken out from pack & 20 ml of orange juice mixed in pack so the new ratio of mango juice & orange juice become 7:5
- The quantity of mango juice taken out from Puch initially.
- Let the total quantity of juice = 280ml.
- The ratio of mango to orange juice part is 9:5.
Thus, volume of mango juice.
9/(9+5) × 280
9/14 × 280
180ml.
Volume of orange juice
5/14 × 280ml
100ml.
y, ml of mango juice is taken out.
so, mango juice remaining = (180 - y)ml.
and, 20ml orange juice is added so, orange juice.
(100 + 20)ml.
120ml.
So, mango to orange juice ratio now.
(180 - y)/120
Given the ratio = 7:5
so,
(180 - y)/120 = 7/5
840 = 900 - 5y
5y = 900 - 840
5y = 60
y = 60/5
y = 12ml.
Hence, 12ml of mango juice was removed.