Question

A particle of mass 0.1 kg has an initial speed of 4ms ^−1 at a point on a rough horizontal road. The coefficient of friction between the object and road is 0.15 the particle moves to a point B at a distance of 2m from A. What is the speed of particle at B? Take g=10 ms ^−2

Answer 1

Explanation:

m=0.1kg

V

initial

=u=4㎧

μ=0.15s=2m

v

final

=v

v

2

=u

2

−2as

v

2

=16−2×0.15×10×2

=10

v=

10m

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