a+2b+3c=0 then find a³-8b³+27c³
please answer asap
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this pic gives ur answer
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Anonymous:
I am sorry this is wrong answer I had to send to someone else..IAm sorry
ok
i found my answer
hmm
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a+3c=-2b
cube both sides
(a+3c)^3=(-2b)^3
a^3+27c^3+27ac^2+9a^2c=-8b^3
a^3-8b^3+27c^3=2a^3+54c^3+27ac^2+9a^2c
cube both sides
(a+3c)^3=(-2b)^3
a^3+27c^3+27ac^2+9a^2c=-8b^3
a^3-8b^3+27c^3=2a^3+54c^3+27ac^2+9a^2c
then also it is wrong
the solution i posted is for a^3-8b^3+27c^3
its like. (a-2b)=-3c and then cubing both sides
what is the answer given in ur book
its answer is -18abc
u have given a+2b+3c=0 in ur original question post
rhanx but i ve found my answer
thanx
then sorry
no problem
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