A 2digit number is such that the tens digit exceeds thrice 3 the unit digit by 3 and the number odtsined by interchanging the digits is 2 more than twice the sum of the digits find the number
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Let the two digit number be 10x+y where y is units digit and x is ten's digit.
It is given that-
x=2y+2 ...(1)
and 10y+x=3(x+y)+5 ....(2)
an solving equation (2) and (1)
10y+x=3x+3y+5
⇒7y−2x=5
∴7y−2(2y+2)=5
3y−4=5
3y=9
y=3
and x=2y+2=6+2=8
the two digit number is 83
hope this is helpful
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