Question

A(-3,-4) , B(-5,0) ,C(3,0) are the vertices of ∆ABC. Find the co-ordinates of the circumcentre of ∆ABC.
ans this question

Answer 1

Answer:

thus circumcentre = (-1,-1/4)

Step-by-step explanation:

A(-3,-4) ,B(3,0) C(-5,0) and P(a,b)

PA=PB=PC

PA²=PB²

(a+3)²+(b+4)²=(a-3)²+b²

a²+b²+6a+8b+9+16=a²+b²-6a+9

12a+8b=-16

3a+4b=-4...................(1)

PB²=PC²

(a-3)²=(a+5)²

a²-6a+9=a²+10a+25

16a=-16

a=-1

from(1)

-3+4b=-4

4b=-1,b=-1/4

thus circumcentre = (-1,-1/4)