Question

a^3-8b^3-64c^3-24abc

Answer 1

Hey dear!


Here is yr answer.....


=> a³ - 8b³ - 64c³ - 24abc

=> a³ + (-2b)³ + (-4c)³ -3(a)(-2b)(-4c)


It is in the form of ------

[a³ + b³ + c³ -3abc = (a+b+c)(a²+b²+c²-ab-bc-ca)]


a = a, b = -2b , c = -4c


=> [a+(-2b)+(-4c)] [a²+(-2b)²+(-4c)²-(a)(-2b)-(-2b)(-4c)-(-4c)(a)

=> (a-2b-4c) (a²+4b²+16c²+2ab-8bc+4ac)


Hope it hlpz....

Answer 2

hii. ....friend

the answer is here,

$= > {a}^{3} - 8 {b}^{3} - 64 {c}^{3} - 24abc$

This in the form of

$= > \: {a}^{3} + {b}^{3} + {c}^{3} - 3abc = (a + b + c)( {a}^{2} + {b}^{2} + {c}^{2} - ab - bc - ca)$

$= > \: {a}^{3} + ({ - 2b)}^{3} + {( - 4c)}^{3} - 3(a)( - 2b)( - 4c)$

$= > \: ( a - 2b - 4c)( {a}^{2} + 4 {b}^{2} + 16 {c}^{2} + 2ab - 8bc + 4ac)$

:-)Hope it helps u.