Question

a^3+b^3+3a^2•b+3a•b^2-8 factorize?? this equation

Answer 1

a^3+b^3+3a^2b+3ab^2=(a+b)^3. then (a+b)^3-2^3=. (a+b-2)[(a+b)^2+2^2+(a+b)×2)]=(a+b-2)[(a+b){(a+b)+2}+4]=(a+b-2)[(a+b)(a+b+2)+4]. ::a^3-b^3=(a-b)(a^2+ab+b^2):::