Question

Please answer me of this question..!

Answer 1

OP= OQ
therefore,
QR= OQ
So, in Triangle OQR, angle QOR= 20°
So, Angle OQR= 140°-------Sum of angles of triangle is 180°

Therefore, angle OQP= 40°
Angle OQP= Angle OPQ= 40°------Radii of the same circle....

So, in traingle OPQ, Angle O= 100°------ sum of angles of traingle is 180°

Now, TOR is a straight line:
Therefore, Angle O= 180°

Angle TOP + Angle POQ + Angle ROQ= 180°

x°= 180-100-20
x°= 180-120
x°= 60°

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