Question

a^3+b^3+3ab=1 find value of a and b?​

Answer 1

Answer:

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Step-by-step explanation:

a3+b3+3ab−1+3ab(a+b)−3ab(a+b)=0

⟹(a+b)3−13−3ab(a+b−1)=0

⟹(a+b−1)((a+b)2+1+a+b)−3ab(a+b−1)=0

⟹(a+b−1)(a2+b2+ab+a+b+1)=0

Hence

a+b=1