Question

A = 3
B = -5
C = 3

Solve ---

a×a+ b×b + c×c + 2 ( ab+ bc + ca)​

Answer 1

Step-by-step explanation:

3 * 3+-5*-5+3*3(3*-5+-5*3+3*3)

9+25+9(-15-15+9)

43(-30+9)

43(-21)

43*-21

answer = -903

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Answer 2

Answer:

Step-by-step explanation:

Form a3 + b3 + c3 , where a + b + c = 0.

We have, a3 + b3 + c3 = a3 + b3 – (-c)3

                                = a3 + b3 – (a + b)3, [Since, a + b  + c = 0]

                                = a3 + b3 – {a3 + b3 + 3ab(a + b)}

                                = -3ab(a + b)

                                = -3ab(-c)

                                = 3abc

Therefore, a + b + c = 0, a3 + b3 + c3 = 3abc