a 3 cm thick iron open box is made whose external dimensions are 78 cm x 54 cm x 12 cm. find the weight of the box if its density is 60 gm/cm
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Answered by
21
volume of base =78×54×3=12636
volume of 2 opp sides =78×9×3×2=4212
volume of left 2 sides=48×9×3×2=2592
total volume=19440
total weight=19440÷60
=324gm
this is for a box open from top
volume of 2 opp sides =78×9×3×2=4212
volume of left 2 sides=48×9×3×2=2592
total volume=19440
total weight=19440÷60
=324gm
this is for a box open from top
geek1610:
May I know how we got 48 in volume to the left side in the above q
Answered by
10
Answer: 1788.48 Kg
Step-by-step Explanation:
External Volume = 78 x 54 x 12 = 50544 cm^3
Internal Volume = (78 - 3*2) x (54 -3*2) x (12 - 3*2) = 72 x 48 x 6 = 20736 cm^3
External Volume - Internal Volume = 50544 - 20736 = 29808 cm^3
Weight = Volume x Density
Weight = 29808 cm^3 x 60gm/ cm^3 = 29808 x 60 = 1788480 gms =
1788.48 Kg
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