Question

A+3B gives rise to 4C inital concentration of A is equal to B. The equilibrium concentration of A is equal to C. Kc of the reaction

Answer 1

I think this will be the answer.....

Answer 2

Answer:            Kc = 8

Explanation:

GIVEN : initial conc. of A = initial conc. of B

  Equilibrium const. of A = Equilibrium const. of C

              Reaction :       A + 3B → 4C

TO FIND : Kc of the reaction

SOLUTION :

Let the initial conc. of A = initial conc. of B = Y --------- (i)

Let Y*M of A reacts with 3 Y*M of B to form 4Y*M of C (Y* is the conc. reacted )

at eqm. the conc will be

[A] = Y- Y*M

[B] = Y-3Y*M

The eqm. const. of A and C are same

     ∴  Y - Y* = 4Y*

          Y = 5Y* or Y* = 0.2 Y

  Conc. of A at equilibrium = Y - Y*

                                              = Y - 0.2Y = 0.8 Y

Conc. of B = Y - 3Y*

                  = Y - 3(0.2Y) = 0.4 Y M

Conc of C at equilibrium = 4Y*

                                         =  4(0.2Y) = 0.8Y

Kc = [C]⁴ / [A] [B]³

Kc = (0.8Y)⁴ / (0.8Y) (0.4Y)³

Kc = 8

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