A 40kg block is moving to the right with a speed of 1.5m/s...
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According to conservation of energy, energy will be same throughout the path.
So energy at highest point = mgh + 1/2 mv^2.
Here v = 0. (Body is resting).
Therefore, E = mgh = 40 * 10 * 5= 2000 Joules or 2 Kilo Joules.
This is also the energy at a height of 2m from the ground.
So energy at highest point = mgh + 1/2 mv^2.
Here v = 0. (Body is resting).
Therefore, E = mgh = 40 * 10 * 5= 2000 Joules or 2 Kilo Joules.
This is also the energy at a height of 2m from the ground.
rishabh9050p2bux2:
But we need to find the velocty at t=10s.
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