Question

A 42.7 gram sample of potassium nitrate (101.103 g/mol) contains how many grams of oxygen (15.999 g/mol)?

Answer 1

Answer:

hi

Explanation:

Moles KNO3 = 42.7 g / 101.037 g/mol= 0.422

Moles K = 0.422

mass K = 0.422 mol x 39.1 g/mol=16.5

Answer 2

Answer:

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