A 5 kg ball A rolls on smooth surface with a velocity 10 m/s collides with another ball B
of mass 10 kg moving opposite to ball A with a velocity 4 m/s as shown in the following
figure. The coefficient restitution is 0.6 between both the balls. Calculate the velocities of
balls immediately after impact.
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Answer:
Vcommon=5×10+10×4/5+10=90/15=6ms‐¹
fr1=0.6×5×10=30N
fr2=0.6×10×10=60N
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