Physics, asked by rejoycemgele, 1 month ago


A 5 kg block, resting on a rough horizontal surface, is connected by
a light inextensible string passing over a light frictionless pulley to a
second block of mass 3 kg hanging vertically.
An applied force F is acting on the 5 kg block as shown in the
diagram below and the coefficient of kinetic friction between the 5
kg block and the surface is 0,2.
1
The 5 kg block accelerates to the left.
F
20°
5 kg
3 kg
1.1

Define the term frictional force.
(2)
1.2
Calculate the magnitude of the:
1.2.1
Vertical component of F if the magnitude of the
horizontal component of Fequals 38 N
(2)
1.2.2
Normal force acting on the 5 kg block
(3)
1.3
State Newton's Second Law of motion.
(2)
1.4
Draw a labelled free-body diagram to indicate all the
forces acting on the 3 kg block.
(2)
1.5
Calculate the magnitude of the tension force in the string
connecting the two blocks,
[17]​

Answers

Answered by hetaldohare
0

Answer:

5 kg because it would be in 5 kg that's why the answer is 5 kg

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