a 5 kg box on a horizontal table is pushed by horizontal force of 15 Newton find the frictional force acts on it coefficient of friction is 0.4
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Answered by
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Since the limiting frictional force is 0.4*5*9.8N=19.6 N and force P=15 which is less than 19.6 so frictional force is also 15 N
Answered by
0
Answer:
58.8
Explanation:
15×0.4×9.8 = 58.8
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