Question

A 5 rupee coin weighs 9g. What is the weight of a sack with 1100 coins of 5

rupees?​

Answer 1

Answer:

9900

Step-by-step explanation:

because 9×1100=9900

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Answer 2

Answer:

$\Large{\boxed{\red{\underline{9900 \: g \: or \: 9.9 \: kg}}}}$

Step-by-step explanation:

Given,

1 coin (of 5 ruppee) = 9 g

Let the unknown weight of sack of 1100 coins (of 5 ruppees) be $x$.

Then, 1100 coin (of 5 ruppees) = $x$

$\frac{1 \:coin}{1100 \: coin}$$\frac{=}{=}$$\frac{9 \: g}{x}$

$\frac{1}{1100}$=$\frac{9}{x}$

By cross multiplication of numerators to denominators, it becomes,

1 × $x$ = 1100 × 9

$x$ = 9900 g

1 kg = 1000 g

= $\frac{9900}{1000}$ = 9.9 kg

Hence, a sack with 1100 coins of 5 ruppees will have a weight of $\large{\boxed{\red{\underline{9900 \: g \: or \: 9.9 \: kg}}}}$

^^

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