A 6 pole induction motor supplied by a
10 pole alternator which is driven at 600 rpm.
If the motor is running at 970 rpm, determine
the percentage slip.
(A) 3%
(B) 2%
(C) 5%
(D) 1%
Answers
Answered by
3
Answer:
the percentage slip = 3 %
Step-by-step explanation:
For the Alternator P = 10 Speed = 600 RPM
Synchronous Speed = 120f/P
=> 600 = 120 * f /10
=> f = 50 Hz
For induction Motor P = 6
Synchronous Speed = 120 * 50 /6
=> Synchronous Speed = 1000 rpm
Formula for slip id given by
s ={ (Synchronus speed - rotational Speed)/(synchronus speed) } * 100
s ={ ( 1000 - 970)/1000 } * 100
= (30/1000) * 100
= 3 %
the percentage slip = 3 %
Answered by
0
Answer:
Step-by-step explanation:
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