Question

A=9÷3-b
b=9÷3-c
find values

Answer 1

Answer:

A=C

b=3-A

No perfect answer can be made

Answer 2

Answer:

If the question is

A=9÷(3-b) .........Eq1

b=9÷(3-c)........ Eq2

Solving Eq1

A(3-b)=9

3A-Ab=9

Ab=3A-9

b=(3A-9)÷A

Solving Eq 2

b(3-c)=9

Using value of b

[(3A-9)/A][3-c]=9

9A-3Ac+9c-27=9A

3A-Ac+3c-9=3A

3c-Ac=9.....Eq 3

Put b=9÷(3-c) in Eq 1

A=9÷[3-{9/(3-c)}]

After simplification

c-Ac=9......Eq 4

Adding Eq3+Eq4

4c=18

c=18/4=9/2

Put value of c in Eq 2

b=9÷(3-9/2)

b= - 6

Put in eq 1

A=9÷(3-(-6))

A=9/9=1