If the class marks of a continuous frequency distribution are 22,30,38,46,54,62, then the class corresponding to the class mark 46 is
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The corresponding class mark for 42 is 50
Given:
Frequency distribution of marks are "22", "30", "38", "46", "54", "62"
To find:
The corresponding class mark
Answer:
Given that
Class marks are "22", "30", "38", "46", "54", "62"
The difference of class marks are, h=8
Where,
a = class marks and
h =class difference.
Lower \ limit \ of \ class, = a - \frac {h} {2}Lower limit of class,=a−
2
h
Upper \ limit \ of \ class, = a + \frac {h} {2}Upper limit of class,=a+
2
h
Lower \ limit = 46 - \frac {8}{2}Lower limit=46−
2
8
= 46 - 4 = 42=46−4=42
Upper \ limit = 46 + \frac {8}{2}Upper limit=46+
2
8
= 46 + 4=46+4
= 50=50
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