Question

A 905 kg test car travels around a 3.25 km circular track. If the magnitude of the force that maintains the car's circular motion is 2140 N, what is the car's tangential speed?

In my book the anwser is written as 35m/s

but i keep getting 87.6
​

Answer 1

Answer:

39.6341

Explanation:

F=2140

m=905

D=3.25 km

We know that F=ma

2140=905*a

a=2140/905=2.36

a=v-u/t. (v=3.25; u=0)

2.36=3.25-0/t

t=3.25/2.36=1.377 minute

t=82.62 second

s=d/t

s=3250/82.62=39.6341