A screw gauge has least count of 0.02 mm and there are 100 division on its circular scale. The pitch of the screw gauge is O 0.5 mm 0 1 mm O 2 mm 0 0.01 mm
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Given:
least count of screw gauge 0.02 mm
divisions on its circular scale 100
To find:
the pitch of the screw gauge
Solution:
The value of the pitch of a screw gauge is equal to the product of its least count and the number of divisions.
The formula to be used in this questions is
pitch = least count × number of divisions
Substitute the value in the formula
= 0.02 mm × 100
= 2 mm
Therefore, the pitch of a screw gauge with least count 0.02 mm and 100 divisions is 2 mm.
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