A×A ={ a,b,c} × {a,b,c}
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Given A×A= {a,b,c}×{a,b,c}
Here A= a,b,c
Now let us multiple A× A
which is as follows
=> (a,a),(a,b),(a,c),(b,a),(b,b),(b,c),(c,a),(c,b),(c,c)
=> 2(a,a),(b,b),.....so on
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