Question

A aircraft executes a horizontal loop of radius 1 km with a steady speed of 900km/h.Compare it's centripetal acceleration with acceleration due to gravity

Answer 1

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Radius of the loop, r = 1 km = 1000 m

Speed of the aircraft,

v = 900 km/h= 900× 5/18 = 260m/s

Centripetal acceleration,

a(c) = v^2/ r

= (250)^2/1000

= 62.5 m/s^2

Acceleration due to gravity, g = 9.8 m/s2

a(c)/ g

=62.5/9.8

= 6.38

=> a(c)= 9.38 g

I hope, this will help you

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Answer 2

Solution -::

Centripetal acceleration is given by

$a \: = \frac{ {v}^{2} }{r \: }$

we have r = 1 km

=1000 m

v = 900 km/h

$900 \times \frac{1000}{3600} m \s$

$a \: = \frac{ {v}^{2} }{r} = \frac{250 \times 250}{1000}$

$= 62.5m \s$

$g \: = 9.8 \: m\s$

$\frac{a}{g} = \frac{62.5}{9.8} = 6.4$

therefore 6.4 is answer