Math, asked by Elenkalakshmaksha, 1 year ago

A and B can complete a job in 8 days .Both B and C , working alone can finish the same job in 12 days. A and B commence work on job and work for 4 days whereupon A leaves. B continues for 2 more days and then leaves too. C now starts work and finishes the job.How many days does C require

Answers

Answered by 8527838993
1
C complete the work in 6 days
Answered by AkashMandal
1
SOLUTION:-

ns: 4days

here , consider the lcm 72,therfore total work is 72

a,b and c complete by 8 days.

a,b,and c 's1 days work is 72/8=9units.

b and c 's 1 day work is 72/12=6units.

now, a and b work 4 days ,so 4×9=36units.

then, remaining work is 72-36=36units.

now, b continuos for 2 days.

then ,remaining work is 36-(6×2)=24units

c's 1 day work is 6units

so, 24/6=4days

c can complete complete the work in 4 days(Ans)..
Similar questions