calculate the number of particles present in 17.75g of HCl
Answers
Answered by
1
Given mass of HCL = 17.75 g
we know that
molar mass of HCL = 1x(1)+ 1x(35.5) = 36.5
⇒moles of HCL = 17.75/36.5
= 0.48 moles
Now we know that
No of particles = moles x avagadro number
=0.48 x 6.022 x
=2.89 x
-----------------------------------------------------------------------------------------------------------------
Best of luck ;)
ROYALJATT
we know that
molar mass of HCL = 1x(1)+ 1x(35.5) = 36.5
⇒moles of HCL = 17.75/36.5
= 0.48 moles
Now we know that
No of particles = moles x avagadro number
=0.48 x 6.022 x
=2.89 x
-----------------------------------------------------------------------------------------------------------------
Best of luck ;)
ROYALJATT
Answered by
0
HI there !!
HCl = Hydrogen chloride
Molar mass of Hydrogen (H) = 1 u
Molar mass of Chlorine (Cl) = 35.5 u
Molar mass of HCl = 35.5 + 1 = 36.5 u
Given mass = 17.75 grams
No: of moles = Given mass / Molar mass
= 17.75 / 36.5
= 0.48 moles [ approx.]
No: of particles = No: of moles × Avogadro no:
= 0.48 × 6.022 × 10²³
= 2.89056 × 6.022 × 10²³ particles
HCl = Hydrogen chloride
Molar mass of Hydrogen (H) = 1 u
Molar mass of Chlorine (Cl) = 35.5 u
Molar mass of HCl = 35.5 + 1 = 36.5 u
Given mass = 17.75 grams
No: of moles = Given mass / Molar mass
= 17.75 / 36.5
= 0.48 moles [ approx.]
No: of particles = No: of moles × Avogadro no:
= 0.48 × 6.022 × 10²³
= 2.89056 × 6.022 × 10²³ particles
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