Physics, asked by reh2ajonehapra1cy, 1 year ago

calculate the number of particles present in 17.75g of HCl

Answers

Answered by ROYALJATT
1
Given mass of HCL =  17.75 g
 we know that 
molar mass of HCL = 1x(1)+ 1x(35.5) = 36.5
⇒moles of HCL = 17.75/36.5
                          = 0.48 moles

Now we know that 
No of particles = moles x avagadro number
                        =0.48 x 6.022 x  10^{23}
                        =2.89 x  10^{23}

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Best of luck ;)
ROYALJATT
Answered by Anonymous
0
HI there !!

HCl = Hydrogen chloride

Molar mass of Hydrogen (H) = 1 u

Molar mass of Chlorine (Cl) = 35.5 u

Molar mass of HCl = 35.5 + 1 = 36.5 u

Given mass = 17.75 grams

No: of moles = Given mass / Molar mass

= 17.75 / 36.5
= 0.48 moles [ approx.]

No: of particles = No: of moles × Avogadro no:
= 0.48 × 6.022 × 10²³
= 2.89056 × 6.022 × 10²³ particles
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