a and b can do a job in 12 days,after working for 2 days,they are assisted by c,who works at the same rate as a. the work takes 6 1/4 days more to finish. in how many days will b alone do the work?
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Answered by
1
According to question
1/a + 1/b = 1/12
and
also 1/a + 1/b + 1/c = 1/10 + 25/4 = 4/73
Thus putting the values we get
1/12 + 1/c = 4/73
1/c = 1/12 - 4/73
1/c = 25/ 876
1/a + 1/b = 1/12
and
also 1/a + 1/b + 1/c = 1/10 + 25/4 = 4/73
Thus putting the values we get
1/12 + 1/c = 4/73
1/c = 1/12 - 4/73
1/c = 25/ 876
Answered by
13
I hope that it will helps you.
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