Math, asked by MehwishHuma, 1 year ago

A and B can do a job in 6 day if a do the job alone he takes 10 days how many days required by B to complete the job alone​

Answers

Answered by pathak1624
0

Answer:

b will complete the work in 4 days

Step-by-step explanation:

(A+B)= 6 days

(A) alone = 10 days

time needed for (B) to complete = (a+b)-(a)

= 10-6 = 4 days

Answered by parijindal7688
0

Step-by-step explanation:

efficiency is inversely related to time

time taken by both a and B together will be 1/6

time taken by a to complete a work is 1/10

time taken by b to complete the work is 1/x

1/x+1/10=1/6

lcm

x+10/10x =1/6

10+x=10x/6

10+x=5x/3

30+3x=5x

2x=30

x=15

time taken by b is 15 days

Similar questions