A and B can do a job in 6 day if a do the job alone he takes 10 days how many days required by B to complete the job alone
Answers
Answered by
0
Answer:
b will complete the work in 4 days
Step-by-step explanation:
(A+B)= 6 days
(A) alone = 10 days
time needed for (B) to complete = (a+b)-(a)
= 10-6 = 4 days
Answered by
0
Step-by-step explanation:
efficiency is inversely related to time
time taken by both a and B together will be 1/6
time taken by a to complete a work is 1/10
time taken by b to complete the work is 1/x
1/x+1/10=1/6
lcm
x+10/10x =1/6
10+x=10x/6
10+x=5x/3
30+3x=5x
2x=30
x=15
time taken by b is 15 days
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