A and B can do a piece of work in 20 days and B in 15 days. They work together for 2 days and then A goes away. In how many days will B finish the remaining work?
Answers
Given:
Number of days in which A can complete the work = 20
Number of days in which B can complete the work = 15
To find:
In how many days B finishes the remaining work.
Solution:
Let the amount of work be x.
In one day A can complete x/20 amount of work.
In one day B can complete x/15 amount of work.
When they work for two days, amount of work completed = 2* (x/20 + x/15)
= 2* ((3x + 4x)/ 60) = 2* 7x/ 60 = 7x/ 30
Amount of work left = x - 7x/30 = 23x/30
If B completes x/15 amount of work in one day then he would complete 23x/30 amount of work in:
(23x/30) / (x/15) = 12.5 days
Therefore B would take 12.5 days to complete the rest of the work.
Answer:
Step-by-step explanation:
Number of days in which A can complete the work = 20
Number of days in which B can complete the work = 15
To find:
In how many days B finishes the remaining work.
Solution:
Let the amount of work be x.
In one day A can complete x/20 amount of work.
In one day B can complete x/15 amount of work.
When they work for two days, amount of work completed = 2* (x/20 + x/15)
= 2* ((3x + 4x)/ 60) = 2* 7x/ 60 = 7x/ 30
Amount of work left = x - 7x/30 = 23x/30
If B completes x/15 amount of work in one day then he would complete 23x/30 amount of work in:
(23x/30) / (x/15) = 12.5 days
Therefore B would take 12.5 days to complete the rest of the work.