Question

A and B can do a piece of work in 3 days, B
and C in 4 days, C and A in 4 days. The time
taken by C alone to do it is :​

Answer 1

Step-by-step explanation:

A+B=3

B+C=4

C+A=4

C=4-A

B+4-A=4

A-B=0

Now, Eliminating A-B=0 abd A+B=3 we get,

A+B=3

A-B=0

Therefore,A=3/2

C=4-3/2

C=5/2 or 2.5

Therefore the required time taken by C is 2.5 days

Answer 2

Answer:

3,4,4 lcm = 12 ( total work)

efficiency = 4,3,3 (A+B,B+C,C+A)

2(A+B+C) = 4+3+3

(A+B+C) = 9/2 = 4.5 unit

C alone efficiency = 4.5 -(A+B) = 4.5-4 = 0.5 unit /day .

C alone will take = 12/0.5 = 24 days (Ans.)

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