Question

A and B can do work in 60 days, B and C can do the same work in 40 days. If time taken by A alone is 4 days more than the time taken by C alone, then in how many days work will be completed by A and C together? (Consider B is doing negative work)

Answer 1

Answer:

Step-by-step explanation:120/11

Answer 2

A and C together will complete the work in 72 days.

We can use the formula:$1/A + 1/B = 1/X,$

where A and B are the number of days taken by two workers to complete a task, X is the number of days taken by both workers to complete the same task.

We know that A and B can do the work in 60 days and B and C can do the same work in 40 days. So, we can use this information to find the time taken by A and C together to complete the work.

$1/A + 1/C = 1/X$

We know that time taken by A alone is 4 days more than the time taken by C alone.

Let's assume the time taken by C alone is x, then the time taken by A alone will be (x + 4) days.

We can use this information to find the value of X:

$1/(x+4) + 1/x = 1/X$

Solving the equation, we get X = 72 days.

So, A and C together will complete the work in 72 days.

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