A and b set out at the same time to walk towards each other respectively from a place p and q 144 km apart. A walks at the constant speed of 8 km/h, while b walks 4 km in the first hour, 5 km in the second hour, 6 km in the third hour and so on. Then the a will meet b at?
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A will meet B at 10hrs a 80 b 64=144km in 10hrs
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