Question

A and B throw a pair of dice. If A throws 9 find B's chance of throwing the higher number

Answer 1

6/16 will be the probability

Answer 2

Question:-

A and B throw a pair of dice. If A throws 9, find B’s chance of throwing a higher number .

Given:-

A pair of dice is thrown

Required to find:-

Probability that the total of numbers on the dice is greater than 9

First let’s write the all possible events that can occur

$\begin{array}{cccccc}(1,1), &(1,2),& (1,3), &(1,4),& (1,5),& (1,6),\\(2,1), &(2,2), &(2,3), &(2,4),& (2,5), &(2,6),\\(3,1), &(3,2),& (3,3), &(3,4), &(3,5), &(3,6), \\ (4,1), &(4,2), &(4,3),& (4,4), &(4,5), &(4,6),\\ (5,1),& (5,2),& (5,3), &(5,4), &(5,5), &(5,6),\\(6,1), &(6,2), &(6,3), &(6,4), &(6,5), &(6,6),\end{array}$

It’s seen that the total number of events is 62 = 36

Favourable events i.e. getting the total of numbers on the dice greater than 9 are  (5,5), (5,6), (6,4), (4,6), (6,5) and (6,6).

So, the total number of favourable events i.e. getting the total of numbers on the dice greater than 9 is 6

We know that, Probability = $\sf \dfrac{Number ~of ~favourable ~outcomes}{Total ~number ~of~ outcomes}$

Thus, the probability of getting the total of numbers on the dice greater than 9 = $\sf \dfrac{6}{36}$ = $\sf \dfrac{1}{6}$

_______________________