Question

A and b working independently take 36 and 16 days respectively more than the days theytake when they work together.in how many days can b alone complete the work

Answer 1

bbc a good idea how are not going

Answer 2

Answer:

40 days

Step-by-step explanation:

Let the number of the days A and b work together to complete the work be

x

A and b working independently take 36 and 16 days respectively more than the days they take when they work together

So, A can complete work alone in days = x+36

A can complete work alone in 1 day = $\frac{1}{x+36}$

B can complete work alone in days = x+16

B can complete work alone in 1 day = $\frac{1}{x+16}$

So, A and be can do work together in 1 day =$\frac{1}{x+36}+\frac{1}{x+16}$

Since we know that A and B can do  work together in x days = 1

A and B can do work together in 1 day = $\frac{1}{x}$

So, $\frac{1}{x+36}+\frac{1}{x+16}=\frac{1}{x}$

$x\left(x+16\right)+x\left(x+36\right)=\left(x+36\right)\left(x+16\right)$

$x=24,\:x=-24$

Since days cannot be negative

So, neglect - 24

B can complete work alone in days = x+16 = 24+16=40

Hence B can complete work alone in 40 days