a/(ax-1)+b/(bx-1)=a+b solve it for x
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★ QUADRATIC RESOLUTION AND PARTIAL EVALUATION ★
a / ax - 1 + b / bx - 1 = a + b
a(bx - 1) + b( ax - 1 ) / ax - 1 ( bx - 1 ) = a + b
abx - a + abx - b / ax - 1 ( bx - 1 ) = a + b
2abx - 1 ( a + b ) / ax -1 ( bx - 1 ) = a + b
a + b [ ax - 1 ( bx - 1 ) ] = 2abx - 1 ( a + b )
a + b [ abx² - ax - bx + 1 ] = 2abx - 1 ( a + b )
Furthermore , it'll resolve in quadratic equation under " x "
Aslike ,
x² ( a²b + ab² ) - x ( 4ab + a² + b² ) + 2 ( a + b ) = 0
By applying standard quadratic formula , we obtain roots as , or the value of " x " as ...
4ab + a² + b² ± √ ( 4ab + a² + b² )² ( 2 ) a + b / 2 ( a²b + ab² )
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a / ax - 1 + b / bx - 1 = a + b
a(bx - 1) + b( ax - 1 ) / ax - 1 ( bx - 1 ) = a + b
abx - a + abx - b / ax - 1 ( bx - 1 ) = a + b
2abx - 1 ( a + b ) / ax -1 ( bx - 1 ) = a + b
a + b [ ax - 1 ( bx - 1 ) ] = 2abx - 1 ( a + b )
a + b [ abx² - ax - bx + 1 ] = 2abx - 1 ( a + b )
Furthermore , it'll resolve in quadratic equation under " x "
Aslike ,
x² ( a²b + ab² ) - x ( 4ab + a² + b² ) + 2 ( a + b ) = 0
By applying standard quadratic formula , we obtain roots as , or the value of " x " as ...
4ab + a² + b² ± √ ( 4ab + a² + b² )² ( 2 ) a + b / 2 ( a²b + ab² )
★✩★✩★✩★✩★✩★✩★✩★✩★✩★✩★
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