Question

A+B=135 1+cosa×1+cosB​

Answer 1

​Answer:

Ans:2

Step-by-step explanation:

Please do correction in question as :

If A+B=135 then find the value of (1+cotA)×(1+cotB​)

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A+B=135

So tan135=(tanA+tanB)/(1-tanAtanB)

tan(90+45)=(tanA+tanB)/(1-tanAtanB)

-cot45=(tanA+tanB)/(1-tanAtanB)

-1=(tanA+tanB)/(1-tanAtanB)

tanA+tanB =tanA tanB-1

Now (1+cotA)(1+cotB)

=(1+1/tanA)*(1+1/tanB)

=1+ 1/tan A + 1/tan B+ 1/tanAtanB

=1+(tanA+tanB)/tanAtanB +1/tanAtanB

=1+(tanAtanB-1)/tanAtanB + 1/tanAtanB

=1 + tanAtanB/ tanAtanB - 1/tanAtanB + 1/tanAtanB

=1+1 =2

Answer 2

A + B = 135

I can't understand your question.....