(a+b)2
![(a + b)2 (a + b)2](https://tex.z-dn.net/?f=%28a+%2B+b%292+)
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Hope it will help you .
Answered by
5
hiii!!!
here's ur answer...
there are many identities in algebraic expressions and (a+b)² is one of them.
( a + b )² = a² + 2ab + b²
lemme give u some example...
→ solve ( 4 + 6 )² with proper identify.
we know that ( a + b )² = a² + 2ab + b²
here a = 4 and b = 6
therefore ( 4 + 6 )²
= 4² + 2 ( 4 × 6 ) + 6²
= 16 + 2 ( 24 ) + 36
= 16 + 48 + 36
= 100
→ second example is with variables..
solve ( 3x + 4y )²
( a + b )² = a² + 2ab + b²
a = 3x and b = 4y
= (3x)² + 2 ( 3x ) ( 4y ) + ( 4y )²
= 9x² + 24xy + 16y²
hope u understood...
and also helps u..!!
here's ur answer...
there are many identities in algebraic expressions and (a+b)² is one of them.
( a + b )² = a² + 2ab + b²
lemme give u some example...
→ solve ( 4 + 6 )² with proper identify.
we know that ( a + b )² = a² + 2ab + b²
here a = 4 and b = 6
therefore ( 4 + 6 )²
= 4² + 2 ( 4 × 6 ) + 6²
= 16 + 2 ( 24 ) + 36
= 16 + 48 + 36
= 100
→ second example is with variables..
solve ( 3x + 4y )²
( a + b )² = a² + 2ab + b²
a = 3x and b = 4y
= (3x)² + 2 ( 3x ) ( 4y ) + ( 4y )²
= 9x² + 24xy + 16y²
hope u understood...
and also helps u..!!
abhi569:
Np??
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