Math, asked by akhilesh6207326, 8 months ago

(a-b)3-(b-c)3+(c-a)3+3(a-b)(b-c)(c-a)

Answers

Answered by marrymallick7629

1

Answer:

2c3-2b3-6a2b+6ab2-6c2a+6ca2

Step-by-step explanation:

(a-b)3-(b-c)3+(c-a)3+3(a-b)(b-c)(c-a)

=(a3-3a2b+3ab2-b3)-(b3-3b2c+3bc2-c3)+(c3-3c2a+3ca2-a3)+(3ab2-3ac2-3a2b+3bc2+3ca2-3b2c)

=a3-3a2b+3ab2-b3-b3+3b2c-3bc2+c3+c3-3c2a+3ca2-a3+3ab2-3c2a-3a2b+3bc2+3ca2-3b2c

=2c3-2b3-6a2b+6ab2-6c2a+6ca2

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