Question

(a-b)³+(b-c)³+(c-a)³​

Answer 1

(a-b)^3 + (b-c)^3 +(c-a)^3

= a^3+3ab^2 -- 3a^2b --b^3 +b^3 --c^3+ 3bc^2 --3b^2c +c^3--a^3 +3ca^2--3c^2a

= 3ab^2 --3a^2b +3bc^2 -- 3b^2c + 3ca^2--3c^2a

= 3ab(b-a) +3bc(c-b) + 3ac(a-c)

Answer 2

Answer:

Step-by-step explanation:

(a-b)³= a³-b³-3a²b + 3ab²

(b-c)³ = b³ -c³ - 3b²c + 3c²b

(c-a)³ = c³ - a³ - 3a²c + 3 c²a

now substitute in question

-3a²b +3ab²-3b²c +3c²b - 3a²c +3c²a

3ab(b-a) + 3bc(c-b) +3ac(c-a)

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