a+b=3 then what is the value of a³+b³
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if a+b=3
then cubing both side we get
a³+b³+3ab(a+b)=27so a³+b³=27-3ab(b+a)
then cubing both side we get
a³+b³+3ab(a+b)=27so a³+b³=27-3ab(b+a)
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a+b=3
a³+b³+3ab(a+b)=27
so a³+b³=27-3ab(b+a)
= 27 - 3 ab^2 - 3a^2b
a³+b³+3ab(a+b)=27
so a³+b³=27-3ab(b+a)
= 27 - 3 ab^2 - 3a^2b
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