Math, asked by HEMANTHKUMAR007, 10 months ago

( a + b ) ^4 = ..................


amitnrw: ((a^2+b^2) + 2ab)^2 = (a^2+b^2)^2 + 4a^2b^2 + 2×2ab(a^2+b^2)
amitnrw: a^4+b^4+6a^2b^2+4a^3b +4ab^3
HEMANTHKUMAR007: pls answer u
amitnrw: Two people are already writing , so i can't
HEMANTHKUMAR007: oh ok
HEMANTHKUMAR007: thanks
amitnrw: Welcome

Answers

Answered by Anchalsinghrajput
1
heya your answer is here....
by using binomial theorem...hope it helps...
Attachments:
Answered by amitnrw
1

Answer:

a^4 + b^4 + 6a^2b^2 + 4a^3b + 4ab^3


Step-by-step explanation:

(a+b)^4

=( (a+b)^2)^2

=(a^2 +b^2+2ab)^2

= ((a^2+b^2)+(2 a b))^2

= (a^2 + b^)^2 + (2ab)^2 + 2(a^2+b^2)(2ab)

= a^4 + b^4 + 2a^2b^2 + 4a^2b^2 + 4a^3b + 4ab^3

= a^4 + b^4 + 6a^2b^2 + 4a^3b + 4ab^3


amitnrw: Thanks for brainliest
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