Question

a+b=9 and ab=18 if a-b what

Answer 1

• a+b = 9
• ab = 18
• a² + b² = (a+b)² - 2 ab

                   = 9² - 2 x 18

                   = 81 - 36

                   = 45

Again

a²+b²=(a-b)²+2 ab

⇒ 45 = (a-b)² + 2 x 18

⇒ (a-b)² = 45-36

⇒ (a-b)² = 9

∴ a-b = 3

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Answer 2

$\huge\bold\red{SOLUTION:-}$

☯ Answer:-

→ a-b = 3

☯ Step-by-step explanation:-

We are given that,

#a+b = 9

and

#ab= 18.

Now,

As we know,

a² + b² = (a+b)² - 2ab

Therefore, on substituting the given values, we get,

a² + b² = (9)² - 2(18)

= 81 -36

= 45

Again,

a² + b² = (a-b)² + 2ab

Now, from our previous solvings we have a²+b² = 45. So, all we'll be doing is just substituting the above-mentioned value.

Here we go!

=> 45 = (a-b)² + 2 × 18

=> (a-b)² = 45 - 36

=>(a-b)² = 9

➡ a-b = √9 = 3

[The required answer!]

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