Question

A+B=90,then find tanA tanB +tanA cotB/sinA secB - sin^2B/cos^2A

Answer 1

Given, LHS = root tan a tan b + tan a cot b/sin a sec b - sin^2 b/cos^2 a

     = root tan a tan(90-a) + tan a cot(90-a)/sin a sec(90-a) - sin^2(90-a)/cos^2 a

     = root tan a.cot a + tan a.tana/sin a.cosec a - cos^2 a/cos^2 a

     = root 1+tan^2 a/1 - 1

    = root tan^2 a

   = tan a.

Hope this helps!

Answer 2

hey there is answer !!
I hope you help !!
mark me brainlist !!

see the pic I send it !!