Math, asked by abdulsalamquadriabdu, 2 months ago

(a + b) (a - b) = a2– b2​

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Answered by Anonymous
24

\huge\color{cyan}\boxed{\colorbox{black}{solution}}

 =  >  \: (a + b)(a - b) =  {a}^{2} -  {b}^{2}

 =>a(a - b) +b(a - b) ={a}^{2} -  {b}^{2}

 =  >  \:  {a}^{2} - ab + ba -  {b}^{2} =  {a}^{2}   -  {b}^{2}

 =  >  {a}^{2} -  {b}^{2} - ab + ba =  {a}^{2} -  {b}^{2}

 =  >  {a}^{2} -  {b}^{2}  =  {a}^{2}  -  {b}^{2}

Answered by ItzMeMukku
1

\huge\rm\color{red}{here\:it\:goes}\color{red}\downarrow{}

  \: (a + b)(a - b) = {a}^{2} - {b}^{2}

 a(a - b) +b(a - b) ={a}^{2} - {b}^{2}

 \: {a}^{2} - ab + ba - {b}^{2} = {a}^{2} - {b}^{2}

{a}^{2} - {b}^{2} - ab + ba = {a}^{2} - {b}^{2}

 {a}^{2} - {b}^{2} = {a}^{2} - {b}^{2}

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More info :-

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\begin{gathered}\boxed{\begin{array}{| c |}\qquad\tt\large\textsf{ ! Formulas ! }\\\\\\\qquad\tt{:}\longrightarrow\large\textsf{ ( a + b )² = a² + 2ab + b² }\\\\\\\qquad\tt{:}\longrightarrow\large\textsf{ ( a - b )² = a² - 2ab + b² }\\\\\\\qquad\tt{:}\longrightarrow\large\textsf{ a² - b² = ( a + b ) ( a - b ) }\\\\\\\qquad\tt{:}\longrightarrow\large\textsf{ ( a + b )³ = a³ + 3a²b + 3ab² }\\\\\\\qquad\tt{:}\longrightarrow\large\textsf{ ( a - b )³ = a³ - 3a²b + 3ab² - b³ }\\\\\\\qquad\tt{:}\longrightarrow\large\textsf{ a³ - b³ = ( a - b ) ( a² + ab + b² ) }\end{array}}\end{gathered}

Thankyou :)

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