(a×b)(b×c)(c×a)=(abc)2
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=(a×b)(b×c)(c×a) =(abc)²
=a×b×b×c×c×a
=a²×b²×c²
or.= (abc)²
=R.H.S.
hence proved...
=a×b×b×c×c×a
=a²×b²×c²
or.= (abc)²
=R.H.S.
hence proved...
Answered by
0
LHS = (a×b)(b×c)(c×a)
= a×b×b×c×c×a
= a×a×b×b×c×c
= a^2 × b^2 × c^2
= (abc)^2=RHS (verified)
Hope this helps.
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= a×b×b×c×c×a
= a×a×b×b×c×c
= a^2 × b^2 × c^2
= (abc)^2=RHS (verified)
Hope this helps.
Mark me brainliest
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